It's easy to evalute (a + b + c)2.....
Let x = (a + b)....then expand (x + c)2 as you would normally in the case of binomial expansion......which is :
(x + c)2 = x2 + c2 + 2xc ......(1)
Now, replace x with (a + b) in (1).....then it becomes.......
(a + b)2 + c2 + 2.(a + b).c .....(2)
Just a little more to be done here ( now we expand (2) in the last step)........
a2 + b2 + 2ab + c2 + 2ac + 2bc (rearranging this we get)
a2 + b2 + c2 + 2ab + 2bc + 2ac .
this happens to be the expansion for (a + b = c)2
If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.
a2+b2+c2-2ab+2bc-2ca
C Natural is a whole step above B flat. If you look at a piano, a half step above B Flat is B Natural, and one more half step above that is C Natural. So it's a whole step from B Flat to C Natural.
Let x be the parameter to be taken square root. a = 0 b = x loop: c = (a+b)/2 if c*c > x then b = c else a = c Repeat until accurate enough result is obtained in c or until c*c equals x.
It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.
(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac
1.774225a
(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac
If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.
a2+b2+c2-2ab+2bc-2ca
Suppose sqrt(A) = B ie the square with sides B has an area of A and its perimeter is 4*B. Now consider a rectangle with sides C and D whose area is A. So C*D = A = B*B so that D = B*B/C Perimeter of the rectangle = 2*(C+D) = 2*C + 2*D = 2*C +2*B*B/C Now consider (C-B)2 which, because it is a square, is always >= 0 ie C*C + B*B - 2*B*C >= 0 ie C*C + B*B >= 2*B*C Multiply both sides by 2/C (which is >0 so the inequality remains the same) 2*C + 2*B*B/C >= 4*B But, as shown above, the left hand side is perimeter of the rectangle, while the right hand side is the perimeter of the square.
The expression ( (A - b + C)^2 ) can be expanded using the formula for the square of a binomial, which states that ( (x + y)^2 = x^2 + 2xy + y^2 ). In this case, it expands to ( (A - b + C)(A - b + C) ), resulting in ( A^2 - 2Ab + 2AC + b^2 - 2bC + C^2 ). Thus, the value of ( (A - b + C)^2 ) is ( A^2 + b^2 + C^2 - 2Ab + 2AC - 2bC ).
(a+b+c) 2=a2+ab+ac+ba+b2+bc+ca+cb+c2a2+b2+c2+2ab+2bc+2ca [ ANSWER!]
C Square
One whole step above B is C#. In musical terms, a whole step consists of two half steps, and moving from B to C# involves skipping B# (which is enharmonically equivalent to C) and landing on C#.
a^2 + b^2 + c^2 - ab - bc - ca = 0=> 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca = 0 => a^2 - 2ab + b^2 + b^2 - 2bc + c^2 + c^2 - 2ca + a^2 = 0 => (a - b)^2 + (b - c)^2 + (c - a)^2 = 0 Each term on the left hand side is a square and so it is non-negative. Since their sum is zero, each term must be zero. Therefore: a - b = 0 => a = b b - c = 0 => b = c.
A is proportional to C4.