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It's easy to evalute (a + b + c)2.....
Let x = (a + b)....then expand (x + c)2 as you would normally in the case of binomial expansion......which is :
(x + c)2 = x2 + c2 + 2xc ......(1)
Now, replace x with (a + b) in (1).....then it becomes.......
(a + b)2 + c2 + 2.(a + b).c .....(2)
Just a little more to be done here ( now we expand (2) in the last step)........
a2 + b2 + 2ab + c2 + 2ac + 2bc (rearranging this we get)
a2 + b2 + c2 + 2ab + 2bc + 2ac .
this happens to be the expansion for (a + b = c)2
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A minus b plus c whole square?
If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.
What is a minus b minus c whole square?
a2+b2+c2-2ab+2bc-2ca
What is a whole step above b?
C Natural is a whole step above B flat. If you look at a piano, a half step above B Flat is B Natural, and one more half step above that is C Natural. So it's a whole step from B Flat to C Natural.
How is the square root of a number found?
Let x be the parameter to be taken square root. a = 0 b = x loop: c = (a+b)/2 if c*c > x then b = c else a = c Repeat until accurate enough result is obtained in c or until c*c equals x.
What is the square root of a squared plus b squared?
It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.
Project on the whole square of a plus b plus c?
(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac
What the average value a-b - whole square b-c whole square c-d whole square d-e whole square e-f whole square f-g whole square over all possible arrangmetns abcdefg of the 7 numbers 1 2 3 11 12 13 14?
1.774225a
A plus b-c whole square?
(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac
A minus b plus c whole square?
If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.
What is a minus b minus c whole square?
a2+b2+c2-2ab+2bc-2ca
Show that among all rectangles with area A the square has the minimum perimeter?
Suppose sqrt(A) = B ie the square with sides B has an area of A and its perimeter is 4*B. Now consider a rectangle with sides C and D whose area is A. So C*D = A = B*B so that D = B*B/C Perimeter of the rectangle = 2*(C+D) = 2*C + 2*D = 2*C +2*B*B/C Now consider (C-B)2 which, because it is a square, is always >= 0 ie C*C + B*B - 2*B*C >= 0 ie C*C + B*B >= 2*B*C Multiply both sides by 2/C (which is >0 so the inequality remains the same) 2*C + 2*B*B/C >= 4*B But, as shown above, the left hand side is perimeter of the rectangle, while the right hand side is the perimeter of the square.
What is a square plus b square?
C Square
A plus b plus c whole square?
(a+b+c) 2=a2+ab+ac+ba+b2+bc+ca+cb+c2a2+b2+c2+2ab+2bc+2ca [ ANSWER!]
Asquare plus b square plus c square -ab -bc -ca equals 0 then show that a equals b equals c?
a^2 + b^2 + c^2 - ab - bc - ca = 0=> 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca = 0 => a^2 - 2ab + b^2 + b^2 - 2bc + c^2 + c^2 - 2ca + a^2 = 0 => (a - b)^2 + (b - c)^2 + (c - a)^2 = 0 Each term on the left hand side is a square and so it is non-negative. Since their sum is zero, each term must be zero. Therefore: a - b = 0 => a = b b - c = 0 => b = c.
If A is proportional to B square and B is proportional to C Square then A is proportional to?
A is proportional to C4.
What appears t be true if A and B are both multiples of a whole number C?
It appears as if A and B are both multiples of a whole number C.
How do you calculate the diagonal in a rectangle?
You do a^2 x b^2 = c^2 where a=the base, b= the height and c=the diagonal.More info: take the square of "a" and the square of "b" and multiply them together, then take your answer and find the square root of it, that is "c" (the diagonal).
