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x = 0 right 2x + 5 = 5 which makes 5 = 5 +2x subtract 5 from each side -5 -5 ---------- 0=0 + 2x 0= 2x substitue x 0 = 2 X 0 solve
I'm assuming it looks like this: 0 > x + 5 > 5 so then the next step is to subtract 5 from every section. -5 > x > 0 And there you go. :]
The equation you are looking for is x + 5 = 0. To solve for x, you would subtract 5 from both sides of the equation. This would give you x = -5. Therefore, -5 plus 5 equals 0.
Add 5 in mod 8. (You can always subtract 3 in mod 8 as well, eg 5 + 3 = 0; 0 - 3 = 5.)
2X - 6X + 5 = 0 subtract 5 from each side 2X - 6X = - 5 do what it says on the left - 4X = - 5 X = 5/4 check in original equation 2(5/4) - 6(5/4) + 5 = 0 10/4 - 30/4 + 5 = 0 - 20/4 + 5 = 0 - 5 + 5 = 0 0 = 0 checks
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5y + x = 0 subtract 5y from each side, then x = -5y
-1,-2,+2,-4,+4,-5,+5, +0. the sequence is subtract twice, add once, subtract again, add, then subtract, then add twice.
Here is an example: x + 5 = 5If you subtract five from both sides, you get x = 0, which is an example of getting 0 as a solution for an equation.
The inverse operation for subtract 5 is add 5. This is because whatever number you start with, if you first "subtract 5" and then "add 5" or if you first "add 5" and then "subtract 5" you are back to the number you started with.