5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.
They are all odd numbers.
no... all numbers that end in 3, 5, 7, and 9 are odd
No, look at 5 it is odd and not divisible by 3. false,because if you look at the 5 it is not divisible by 3.
There are an infinite number of numbers with 3 as a factor. Any number evenly divisible by 3 has 3 as a factor. That means 6, 9, 12, 15, 18, ..., all have 3 as a factor.
All nonzero numbers have factors. Some factors are odd numbers. 3 is an odd factor of 12.
No. A few counterexamples include the numbers 1, 5, 7, and 11, which are all odd numbers but of which 3 is not a factor.
All odd multiples of 3 are not factors of 8.
No odd whole numbers have 12 as a factor. 1 and 3 are odd numbers that are factors of 12.
No. For example: 9 and 27 are both odd but not relatively prime (they both have the factor 3).
Since one is a factor of all non-zero integers, all numbers have common factors.
This can't be determined. The GCF of 3 and 5 is 1. The GCF of 11 and 33 is 11. There's no rule that covers any and all odd numbers.
They are all odd, and they are all prime numbers
The factors of three are both odd numbers.
No
The only number between 3 and 45 which is a factor of 3 is 3. There are several multiples of 3 beyond this.
All even numbers have 2 as a factor, but no odd numbers do. The only even number that will appear as a factor in prime factorizations is 2, because it is the only even prime number. Thus, an odd number will not have even numbers in its prime factorization because an odd number is not evenly divisible by 2. The only even numbers that could appear in the exponential form are the exponents. For example 81 is 34. The factor is an odd number - 3, while the exponent is an even number - 4.