Yes, you can.
Diamagnetic
24edit: nonethe smallest number with 12 distinct factors would be2*3*5*7*11*13*17*19*23*29*31*37>>100
The formula for area which is(Length x Width)times the number of faces on a cube (6). So,(Length x Width) x 6.In the case of side with length 2 it would be2 x 2 x 6Giving us24cm^2
A single number, such as 224243 cannot be relatively prime. And if they are meant to be two numbers, then we cannot tell whether they are meant to be2 and 24243 22 and 4243 224 and 243 2242 and 43 or 22424 and 3. However, you will be pleased to know that the answer is the same in all cases: they are coprime.
Well first of all you find the least common multiple of the denominatorsex:3/5+ 2/9List 5's multiples5: 10 15 20 25 30 35 40 45 50 55 60 65 70Then list 9's multiples9: 18 27 36 45 54 63 72 81 90Then what is the lowest number in the list that they have in common?45!So rename the denominators so that they say /45Then what?You find out what you multiply the first denominator by to get the new denominators5 X 9 = 459 X 5 = 45 (because that's just how it is)So then you have to multiply the numerator by the same number as you multiplied the denominatorSo it would be3 X 9 = 27 So the first fraction would be 27/45and then it would be2 X 5 = 10 So the second fraction would be 10/45THEN ADD!27/45 + 10/45 = 37/45
Yes, Be2-1 exists in the gas phase.
Yes, Be2-1 exists in the gas phase.
be2 is paramagnetic
Be2+ ion has 4 protons and 2 electrons
Beryllium the element (Be) has a zero charge. Beryllium the ion (Be^2+) as a plus 2 charge.
Beryllium is an alkaline earth metal, so its charge will always be Be+2.
0.50
Be2+
Covalent
Diamagnetic
In BeF2 the cation is Be2+.
There would need to be a double bond between the two CH's such as in CH3CH2CH=CHCH2NH2, otherwise the molecule wouldn't exist. The name of this compound would be2-penten-1-amine