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If x is y and y is z which statement must be be true?
If x = y and y = z then x = z
A c plus plus program to read in three integer numbers and print them out in ascending order For example if the numbers input were 10 7 8 then your output would be 7 8 10?
#include <iostream> using namespace std; int main() { int x, y, z; cout << "Enter 3 numbers: \n"; cin >> x; cin >> y; cin >> z; if(x < y && x < z) { cout << x << " "; if(y < z) { cout << y << " " << z; } else if(z < y) { cout << z << " " << y; } } else if(y < x && y < z) { cout << y << " "; if(x < z) { cout << x << " " << z; } else if(z < x) { cout << z << " " << x; } } else if(z < y && z < x) { cout << z << " "; if(y < x) { cout << y << " " << x; } else if(x < y) { cout << x << " " << y; } } char wait; cin >> wait; return 0; }
If you throw 3 coins one with x on 1 side and y on other x on one side and z on other other with y on 1 side and z on other what is theoretical prob of getting 2 that match I don't understand?
3 out of 4. 8 possiableaties------------------ coins 1--- 2--- 3--- 4--- 5--- 6--- 7--- 8 x y--- x--- x--- x--- x--- y--- y---- y--- y x z--- x--- x--- z--- z--- x--- x----z--- z y z--- y----z---y--- z--- y--- z----y-----z There are 8 possiabilities for the three coins to land, you count the matches, there 6 out of 8 that match.
Does division work on distrubitive property?
(x + y)/z = x/z + y/z where z is non-zero.
Find the solution to the system of equations 3x plus y plus z equals 6 3x - y plus 2z equals 9 y plus z equals 3?
3x + y + z = 63x - y + 2z = 9y + z = 3y + z = 3y = 3 - z (substitute 3 - z for y into the first equation of the system)3x + y + z = 63x + (3 - z) + z = 63x + 3 = 63x = 3x = 1 (substitute 3 - z for y and 1 for x into the second equation of the system)3x - y + 2z = 93(1) - (3 - z) + 2z = 93 - 3 + z + 2z = 93z = 9z = 3 (which yields y = 0)y = 3 - z = 3 - 3 = 0So that solution of the system of the equations is x = 1, y = 0, and z = 3.
If xy plus y equals z then x equals?
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
How do you factor y4 - z4?
The expression y^4 - z^4 can be factored using the difference of squares formula. It can be written as (y^2 + z^2)(y^2 - z^2), which can be further simplified to (y^2 + z^2)(y + z)(y - z).
If x is y and y is z which statement must be be true?
If x = y and y = z then x = z
What are the two letters missing om y?
The two letters missing from "y" to complete the English alphabet are "x" and "z." If you are looking for letters that come before "y," they would be "w" and "x." If you meant something different, please clarify!
How do you rewrite an absolute value equation as two linear equations?
x=abs(y+z) x=+(y+z)=y+z x=-(y+z)=-y-z
Possible subsets of x y z?
There are 8 different subsets. The null set. {x} {y} {z} {x y} {x z} {y z} {x y z}
If X Y in Y z which statement must be true?
If x y and y z, which statement is true
What are the boolean theorems?
Commutative x + y = y + x x . y = y . x Associative x+(y+z) = (x+y)+z = x+y+z x.(y.z) = (x.y).z = x.y.z Distributive x.(y+z) = x.y + x.z (w+x)(y+z) = wy + xy + wz + xz x + xy = x x + x'y = x + y where, x & y & z are inputs.
How do you factorise brac x-y brac squared - z sqaured brac. stands for bracket?
(x - y)2 - z2 is a difference of two squares (DOTS), those of (x-y) and z. So the factorisation is [(x - y) + z]*[(x - y) - z] = (x - y + z)*(x - y - z)
A c plus plus program to read in three integer numbers and print them out in ascending order For example if the numbers input were 10 7 8 then your output would be 7 8 10?
#include <iostream> using namespace std; int main() { int x, y, z; cout << "Enter 3 numbers: \n"; cin >> x; cin >> y; cin >> z; if(x < y && x < z) { cout << x << " "; if(y < z) { cout << y << " " << z; } else if(z < y) { cout << z << " " << y; } } else if(y < x && y < z) { cout << y << " "; if(x < z) { cout << x << " " << z; } else if(z < x) { cout << z << " " << x; } } else if(z < y && z < x) { cout << z << " "; if(y < x) { cout << y << " " << x; } else if(x < y) { cout << x << " " << y; } } char wait; cin >> wait; return 0; }
Truth table for 3-inputs OR gate?
It is not easy to illustrate this in a table since it would need to be a 3-d table. The browser which we are required to use is bad enough for ordinary tables. So here goes:X = True, Y = True, Z = True then (X or Y or Z) = TrueX = True, Y = True, Z = False then (X or Y or Z) = TrueX = True, Y = False, Z = True then (X or Y or Z) = TrueX = True, Y = False, Z = False then (X or Y or Z) = TrueX = True, Y = True, Z = True then (X or Y or Z) = TrueX = True, Y = True, Z = False then (X or Y or Z) = TrueX = True, Y = False, Z = True then (X or Y or Z) = TrueX = True, Y = False, Z = False then (X or Y or Z) = FalseThe simple way to remember is that the OR gate gives False only when each input is False.
Does the apostrophe go before or after the letter z?
If it is required, the apostrophe would come after the Z but before the S. "This is Mr. Buzz's stinger!"
