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Evaluate the derivative of the given function at the given point y equals x2 - x equals 3 y equals 6?
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â 11y ago
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Also,
If y = x2 - x then what = 3?
If y = x2 and - x = 3 then y = 6 is inconsistent with the equation of the function.
Wiki User
â 11y ago
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Substitute the given value for the argument of the function.
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If you are actually in your car, check the spedometer. That will tell you your instantaneous velocity; that is, distance traveled per second.If this is a calculus question and you are given the function of your position with respect to time, simply take the derivative of your function and evaluate your derivative at the time at which you would like to determine your instantaneous velocity.Alternatively and more unlikely, you can integrate your acceleration function and solve for your antiderivative based on an initial value given by the context of the problem.
How do you graph and evaluate piecewise functions?
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The gradient of a function, in a given direction, is the change in the value of the function per unit change in the given direction. It is, thus, the rate of change of the function, with respect to the direction. It is generally found by calculating the derivative of the function along the required direction. For a straight line, it is simply the slope. That is the "Rise" divided by the "Run".
How do you find the acceleration and initial velocity given only the distance and time?
If you are only given total distance and total time you cannot. If you are given distance as a function of time, then the first derivative of distance with respect to time, ds/dt, gives the velocity. Evaluate this function at t = 0 for initial velocity. The second derivative, d2s/dt2 gives the acceleration as a function of time.
What is a integration?
the process of finding a function whose derivative is a given function
How do you evaluate a function for a given input value?
Substitute the given value for the argument of the function.
When does the derivative of a function exist at a given point?
Let f be a function and a be the given point you are considering. Then,f(x) - f(a)---------------(x-a)is the difference quotient. If the limit as x approaches a exists, then the function is differentiable at a, or we say the derivative exists at a. If that limit does not exist, then the derivative does not exist at that point.
How do you determine how far your vehicle is traveling per second?
If you are actually in your car, check the spedometer. That will tell you your instantaneous velocity; that is, distance traveled per second.If this is a calculus question and you are given the function of your position with respect to time, simply take the derivative of your function and evaluate your derivative at the time at which you would like to determine your instantaneous velocity.Alternatively and more unlikely, you can integrate your acceleration function and solve for your antiderivative based on an initial value given by the context of the problem.
Why the second derivative negative for Maxima?
When you solve for the 2nd derivative, you are determining whether the function is concave up/down. If you calculated that the 2nd derivative is negative, the function is concave down, which means you have a relative/absolute maximum, given that the 1st derivative equals 0. To understand why this is, think about the definition of the 2nd derivative. It is a measure of the rate of change of the gradient. At a maximum, the gradient starts positive, becomes 0 at the maximum itself and then becomes negative, so it is decreasing. If the gradient is going down, then its rate of change, the 2nd derivative, must be negative.
How would you evaluate the expression 3x-4y equals 9 when x equals 2 and y equals 5?
explain how to evaluate an algebraic expression for given variables. how would we evaluate the expression "3x-4y+9" when x=2and y=5?
What are uses of derivatives?
A derivative of a function represents that equation's slope at any given point on its graph.
What are the uses of derivatives?
A derivative of a function represents that equation's slope at any given point on its graph.
Why does an answer to an integration problem involve a Constant of Integration?
The indefinite integral is the anti-derivative - so the question is, "What function has this given function as a derivative". And if you add a constant to a function, the derivative of the function doesn't change. Thus, for example, if the derivative is y' = 2x, the original function might be y = x squared. However, any function of the form y = x squared + c (for any constant c) also has the SAME derivative (2x in this case). Therefore, to completely specify all possible solutions, this constant should be added.
Evaluate the expression for the given value of the variable 5y - 1 for y equals 3?
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f(x)= â x2fâ˛â˛(x)=?
The function given is (f(x) = -x^2). The second derivative of a function, denoted as (fâ'(x)), measures the concavity of the function. For the function (f(x) = -x^2), the first derivative (fâ(x)) is (-2x). Taking the derivative of (fâ(x)) gives us the second derivative (fââ(x)), which is (-2). So, (fâ'(x) = -2). This indicates that the function (f(x) = -x^2) is concave down for all (x), because the second derivative is negative.
