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1.(x + 2)3 = x3 + 3 · x2 · 2 + 3 · x · 22 + 23 =

= x3 + 6x2 + 12x + 8

2.(3x − 2)3 = (3x)3 − 3 · (3x)2 · 2 + 3 · 3x · 22 − 23 =

= 27x 3 − 54x2 + 36x − 8

3.(2x + 5)3 = (2x)3 + 3 · (2x)2 ·5 + 3 · 2x · 52 + 53 =

= 8x3 + 60 x2 + 150 x + 125

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13y ago

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(×+5)(×+5)=׳+×9+20

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Anonymous

4y ago
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