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Q: Explain the sum of the numbers in each row in Pascal's triangle?

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Each number in Pascal's triangle is used twice when calculating the row below. Consequently the row total doubles with each successive row. If the row containing a single '1' is row zero, then T = 2r where T is the sum of the numbers in row r. So for r=100 T = 2100 = 1267650600228229401496703205376

6^4 = 1296 combinations but some are repeatable e.g. 1221 = 2121 = 2112 etc. so for the total number of non repeatable combinations with 4 dice, use pascals triangle to get 126 unique combinations.

The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)

well first you have to try and figure out what equals 24 but you have to make them add up to the other numbers which are 34 and 44 but they are in a triangle shape 24 (top left) 34 (top right) 44 (bottom of triangle) so can you guys help me answer this thanks for help

One way is: ...1862...2573...3941...

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Each number in Pascal's triangle is used twice when calculating the row below. Consequently the row total doubles with each successive row. If the row containing a single '1' is row zero, then T = 2r where T is the sum of the numbers in row r. So for r=100 T = 2100 = 1267650600228229401496703205376

Scalene

Any three numbers that total 180

To do triangle math on "Brain Age" when there are four numbers on top of the screen, a person has to draw a triangle, then draw a vertical line straight down the middle. Each triangle then shares the line in the middle.

For a triangle to be acute, all the angles are less than 90o. In an equilateral triangle, each angle is the same; thus each is 180o ÷ 3 = 60o and so they are all less than 90o. Therefore a triangle can be both acute and equilateral.

6^4 = 1296 combinations but some are repeatable e.g. 1221 = 2121 = 2112 etc. so for the total number of non repeatable combinations with 4 dice, use pascals triangle to get 126 unique combinations.

There is actually no limit to the number of numbers in Pascal's Triangle. The triangle is simply a way to remember the coefficients of the product of two binomials (or the expansion of a binomial raised to a power). See the link below. The triangle starts like this: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 It goes on forever. Simply begin and end each row with a one and find the numbers in the middle by adding the two above it. Edit: I don't know how to make the above triangle look correct here. The program wants to remove all of the spaces, making the triangle look like a right triangle. Just ignore that. It should look like a pyramid, with the top 1 in the center.

A right triangle can be an isosceles triangle, because the definition of an isosceles triangle is a triangle that has 2 sides equal to each other. A 45,45,90 degree triangle has 2 sides equal to each other, while the hypotenuse is different. It cannot be an equilateral triangle because of the formula a^2+b^2=c^2. With this formula, there is no possible way that: a, b, and c can all be equal to each other. To recap: It can be an isosceles triangle, but not an equilateral one.

All counting numbers. In fact the second number in each row forms the sequence 1,2,3,4,...

The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)

I think if it were to be a triangle that it would be six on each

Of course it can be. It can be anything like x units each of perpendicular and base, and hypotenuse of square root of 2 times x.

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