1) Find two numbers that multiply to -8 and add to 2. Factor of (-8) Sum of (2).
This is 2 * (-4)= -8 and -2 + 4= 2.
2) Then put it in factor mode. (X-2)(X+4). Use distributive property.
3) After that, set it to 0. 0= X-2 Add (+) 2 to both sides.
Cross out the negative and positive 2's. 0 + 2 is 2 = X.
4) Do the same for 4.
5) GGOD LUCK & HOPE U PASS :)
(2x - 1)(5x + 8)
7x2 -4x -5x2 +2x = 2x2 -2x
(2x+3)(2x+4)
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
10x^2 - x - 2 = (5x + 2)(2x - 1)
(x - 2)(2x + 7)
(2x - 3)(x + 2)
(2x-3)(x-1)
(x - 1)(2x - 9)
There is no rational factorisation.
(x - 2)(2x - 3)
(2x - 9)(2x - 9) or (2x - 9)2
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
2x squared - 5x - 3 = (2x +1)(x -3)
2x(2x - 1)
(x - 1)(5x + 7)
(2x - 1)(5x + 8)