1x100/2x2/2x2/2x2/2x2/2x2/2x2/2x2/2+50 + -50 +50=100
2x2 - 16x32 2x2=4-16= -12x32= -384
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
-5
2x2 - 9x + 4 = (2x - 1)(x - 4)
(x-1)(2x+5)
It is: (2x+5)(x-3) when factored
2a(2b) Would Give You The Answer 4ab. 2x2 = 4 And a x b = ab.
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
p2-5p-50= (p-10) (p+5)
1x100/2x2/2x2/2x2/2x2/2x2/2x2/2x2/2+50 + -50 +50=100
Do you mean 2x²? Assuming this is the case: 2x² - 3x + 8x - 12 = 2x² + 5x - 12 = (2x - 3)(x + 4)
Presumably this is a quadratic equation question asking you to find the solution of 2x2+9x-5 = 0 First factorise the expression in the equation in order to find its solution. (2x-1)(x+5) = 0 Solution: x = 1/2 or x = -5
-2x^2 = -50 x^2 = 25 x = 5, -5