Using the vertex (h, k) the equation of the quadratic would be:
y = a(x - h)² + k
→ y = a(x - 8)² + 2
→ y = a(x² - 16x + 64) + 2
→ y = ax² -16ax + 64a + 2
Using the y-intercept of (0, -11):
-11 = a 0² - 16a 0 + 64a + 2
→ 64a = -13
→ a = -13/64
Thus the quadratic could be:
y = (-13/64)x² - 16(-13/64)x + 64(-13/64) + 2
→ y = (-13/64)x² + (13/4)x - 11
Or, removing the fractions: 64y = -13x² + 208x - 704
If the quadratic function is written as ax2 + bx + c, then it has no x-intercepts if the discriminant, (b2 - 4ac), is negative.
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
The quadratic equation is used to find the intercepts of a function (F(x)=x^(2*n), n being an even number) along its primary axis (typically the x axis). Many equations follow this form. The information given by the quadratic equation depends on what your function is pertaining to. If say you have a velocity vs time graph, when the function crosses the xaxis your particle has changed from a positive velocity to a negative velocity. This information can be useful to determine the accompanying behavior of your position. The quadratic equation is simply a tool to find intercepts of a function.
A polynomial function is defined for all x, ranging from minus infinity to plus infinity. Since it is defined for all x, it is defined for x = 0 and this is the point where it intersects the y-axis which is called the y-intercept. It is possible, with suitable choice of coefficients that the function is always positive or always negative. In either case it will not cross the x-axis so that there is no x-intercept. However, it is not true to say that all polynomial functions with real coefficients do not have an x-intercept. In fact all polynomials of odd order (linear, cubic, quintic etc) will have at least one x-intercept.
No, it will be entirely above the x-axis if the coefficient of x2 > 0, or entirely below if the coeff is <0.
y = ax2 + c is a parabola, c is the y intercept of the parabola. It also happens to be the max/min of the function depending if a is positive or negative.
If the quadratic function is written as ax2 + bx + c, then it has no x-intercepts if the discriminant, (b2 - 4ac), is negative.
you distribute the negative to the inside of the parenthesis
It is the equation inside the square root of the Quadratic FormulaIf > 0 there is a solutionIf < 0 there is no solutionBecause you can not calculate the Square Root of a Negative Number
Because in parenthesis you have to multiply it by something.
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
Yes, it can be easily. y=-3x-7 has both a negative slope and a negative y-intercept.
The quadratic has no real solutions.
-54 = -625