0
I think the following 7 are the full set of possible answers:
1998 + 1999 + 2000 + 2001 + 2002 (5 terms)
388 + 389 + ... + 412 (25 terms)
297 + 298 + ... + 328 (32 terms)
18 + 19 + ... + 142 (125 terms)
(-17) + (-16) + ... + 152 (160 terms)
(-296) + (-295) + ... + 328 (625 terms)
(-387) + (-386) + ... + 412 (800 terms).
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Earn +20 ptsQ: Find consecutive integers whose sum is 10000?
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