Q: Find 3 consecutive integers whose sum is 126?

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There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

The numbers are 62 and 64 are two consecutive integers that equal 126.

41,42,43

The numbers are 62 and 64.

:/ We can write it this way: x - 1 + x + x + 1 = 126. 1s cancel out, so we get 3x = 126. 126/3 = 42. Answer: 41, 42, 43.

Related questions

The two even consecutive integers are: 62+64 = 126

41+42+43=126.

Divide 126 by 2 and choose the even numbers on both sides.

63+83=126.... hope it helps!

41, 42 and 43

41, 42 and 43

Let the intgers be n- 1 n , & n+1 . This is consecutive. Hence Adding (n-1) + n + ( n +1) = 126 Add the LHS 3n = 126 Divide both sides by '3' n = 42 Hence n- 1 = 41 & n +1 = 43 So the consecutive integers are 41,42, & 43.

There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

The numbers are 62 and 64 are two consecutive integers that equal 126.

41,42,43

41, 42, 43

The numbers are 125 and 126.