Find minimum point of x2 plus 16 equals 0?

Answer 1

This is the long way:

x2 + 16 = 0

x1= -1/2 + squareroot of -15,75

x2 = -1/2 - sqareroot of - 15,75

Note: squareroot of 16,25 is roughly ~ 4,03112575

Well, so much for the theory, but this question does not have any solution, since you can't draw the squareroot of a negative number like - 15,75.

And the short way:

x2 + 16 = 0

x2 = -16

x = squareroot of - 16, which as I declared above, is not possible.

Woops, I misunderstood your question; heres the answer to your question:

f(x) = x2 + 16

derivate

f'(x) = 2x

f'(0) = 2(0) Put in x = 0

f'(0) = 0 When x = 0, the curve turns and you have a minimi point.

f(0) = x2 + 16 Put in x = 0 in the first equation to get y.

f(0) = 02 + 16

f(0) = 16 y = 16

minimum point: x = 0, y = 16 --> (0;16)