0
This is the long way:
x2 + 16 = 0
x1= -1/2 + squareroot of -15,75
x2 = -1/2 - sqareroot of - 15,75
Note: squareroot of 16,25 is roughly ~ 4,03112575
Well, so much for the theory, but this question does not have any solution, since you can't draw the squareroot of a negative number like - 15,75.
And the short way:
x2 + 16 = 0
x2 = -16
x = squareroot of - 16, which as I declared above, is not possible.
Woops, I misunderstood your question; heres the answer to your question:
f(x) = x2 + 16
derivate
f'(x) = 2x
f'(0) = 2(0) Put in x = 0
f'(0) = 0 When x = 0, the curve turns and you have a minimi point.
f(0) = x2 + 16 Put in x = 0 in the first equation to get y.
f(0) = 02 + 16
f(0) = 16 y = 16
minimum point: x = 0, y = 16 --> (0;16)
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