write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? check bellow link http://bashscript.blogspot.com/2009/08/gcd-of-more-than-two-numbers.html
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Euclid's algorithm is a popular algorithm to compute the GCD of two numbers. Algorithm: Gcd(a,b) = Gcd(b, a mod b), where a>=b and Gcd(a,0) = a Say we want to find the GCD of 72 and 105. 105 mod 72 = 33, so GCD(72,105) = GCD(33,72) 72 mod 33 = 6, so GCD(33,72) = GCD(6,33) 33 mod 6 = 3 so GCD(6,33) = GCD(3,6) 6 mod 3 = 0 so GCD(3,6) = GCD(0,3) = 3. So the GCD of 72 and 105 is 3.
GCD: 4
GCD: 75
if the gcd and lcm are given and one of the numbers are also given,multiply the gcd and lcm and divide them by the given number
GCD = Greatest Common Divisor = Greatest Common Factor = GCF The greatest common factor, or GCF, is the largest positive integer that will divide evenly with no remainder into all the members of a given set of numbers.
write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? check bellow link http://bashscript.blogspot.com/2009/08/gcd-of-more-than-two-numbers.html
I think you meant LCD's and GCD's. GCD (Greatest Common Divisor) It is the largest positive integer that divides the numbers without a remainder. LCD (Lowest Common Denominator) It is the smallest positive integer that is a multiple of the denominators.
To find the greatest common divisor (gcd) of two numbers, you can use methods like prime factorization, Euclidean algorithm, or a GCD calculator. To find the least common multiple (LCM) of two numbers, you can use prime factorization, multiples method, or an LCM calculator.
The greatest common denominator (GCD) refers to a denominator that is COMMON to two or more numbers. You have only one number in the question! The greatest denominator of any number is itself.
Divide the larger number by the smaller one and then replace the larger by the remainder. Repeat until a remainder is 0 or both numbers are 1. In the first case, the non-zero number is the GCD, in the other case, the numbers are coprme: GCD = 1. Thus GCD(85, 102) 102 = 1*85 + R = 17 so GCD(85, 17) 85 = 5*17 + R = 0 so GCD(0, 17) therefore 17. = GCD[85, (102-85)] = GCD(85, 17)
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Shell program for greatest common division (G.C.D.) Of the given three number:-echo "Enter Number 1:-"read aecho "Enter Number 2:-"read becho "Enter Number 3:-"read cgcd=1if [ $a -ge $b ]thens=$aelses=$bfiif [ $s -ge $c ]thent=$selset=$cfii=1while [ $i -le $t ]dod=`expr $a % $i`e=`expr $b % $i`f=`expr $c % $i`if [ $d -eq 0 -a $e -eq 0 -a $f -eq 0 ]thengcd=$ifii=`expr $i + 1`doneecho "The GCD of $a,$b and $c is $gcd"This solution is taken from http://bcahelper.blogspot.com
Euclid's algorithm is a popular algorithm to compute the GCD of two numbers. Algorithm: Gcd(a,b) = Gcd(b, a mod b), where a>=b and Gcd(a,0) = a Say we want to find the GCD of 72 and 105. 105 mod 72 = 33, so GCD(72,105) = GCD(33,72) 72 mod 33 = 6, so GCD(33,72) = GCD(6,33) 33 mod 6 = 3 so GCD(6,33) = GCD(3,6) 6 mod 3 = 0 so GCD(3,6) = GCD(0,3) = 3. So the GCD of 72 and 105 is 3.
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