0
What else can I help you with?
Find the greatest number which divides 742 and 1162 leaves a remainder of exactly 7 in each case?
This is a slight twist to the normal find the GCF of two numbers. In this case as a remainder of 7 is required, subtracting 7 from each number and then finding the GCF of the resulting numbers will solve the problem: 742 - 7 = 735 1162 - 7 = 1155 GCF of 1155 and 735 (using Euclid's method): 1155 / 735 = 1 r 420 735 / 420 = 1 r 315 420 / 315 = 1 r 105 315 / 105 = 3 r 0 GCF of 735 & 1155 is 105, thus 105 is the greatest number that will divide 742 and 1162 leaving a remainder of exactly 7 each time.
What is the greatest number which will divide 11296 so as to leave reminder11?
To find the greatest number that will divide 11296 and leave a remainder of 11, we need to use the concept of divisors. The number that satisfies this condition is called the Greatest Common Divisor (GCD). By using the Euclidean algorithm, we can find that the GCD of 11296 and 11 is 1. Therefore, the greatest number that will divide 11296 and leave a remainder of 11 is 1.
Find the greatest number which divides 6168 2447 and 3118 leaving the same remainder in each case?
Well, honey, the greatest number that fits the bill is the difference between the numbers. So, 6168 - 2447 = 3721, and 3118 - 2447 = 671. The greatest number that divides all three and leaves the same remainder is the greatest common divisor of 3721 and 671, which is 671.
Find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively?
138. What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242 Find hcf of 276 and 1242: 1242 / 276 = 4 r 138 276 / 138 = 2 r 0 hcf of 276 and 1242 is 138. Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
What is the HCF of 35 and 80?
The Highest Common Factor (HCF) of 35 and 80 is the largest number that divides both 35 and 80 without leaving a remainder. To find the HCF, you can use the Euclidean algorithm, which involves dividing the larger number by the smaller number and then dividing the divisor by the remainder until the remainder is zero. The HCF of 35 and 80 is 5.
Find the greatest number which divides 742 and 1162 leaving 7 as remainder in each case?
742/105 = 7 remainder 7 1162/105 = 11 remainder 7
What is the greatest number that divides 364 414 and 539 with the same remainder in each case?
The number is 25.
How do you find the greatest number which divides 319 572 and 1329 leaving remainder 4 5 and 6 respectively?
To find the greatest number that divides 319, 572, and 1329 while leaving remainders of 4, 5, and 6 respectively, we need to use the Chinese Remainder Theorem. First, find the least common multiple of the three given divisors (4, 5, and 6), which is 60. Then, apply the Chinese Remainder Theorem to find the number that satisfies the given conditions. The solution will be the number that is congruent to 4 modulo 4, 5 modulo 5, and 6 modulo 6.
Find the greatest number which divides 742 and 1162 leaves a remainder of exactly 7 in each case?
This is a slight twist to the normal find the GCF of two numbers. In this case as a remainder of 7 is required, subtracting 7 from each number and then finding the GCF of the resulting numbers will solve the problem: 742 - 7 = 735 1162 - 7 = 1155 GCF of 1155 and 735 (using Euclid's method): 1155 / 735 = 1 r 420 735 / 420 = 1 r 315 420 / 315 = 1 r 105 315 / 105 = 3 r 0 GCF of 735 & 1155 is 105, thus 105 is the greatest number that will divide 742 and 1162 leaving a remainder of exactly 7 each time.
How do you make a program to check remainder is zero or not inGW-BASIC?
So you have a number - "Number" and you need to find if the remainder of dividing it by a number is 0. Number = 3 If Number Mod 2 = 0 then Msgbox("Remainder of 0") End If This function divides by 2 then gives the remainder, this let's you check if a number is odd or even.
What is the greatest number which will divide 11296 so as to leave reminder11?
To find the greatest number that will divide 11296 and leave a remainder of 11, we need to use the concept of divisors. The number that satisfies this condition is called the Greatest Common Divisor (GCD). By using the Euclidean algorithm, we can find that the GCD of 11296 and 11 is 1. Therefore, the greatest number that will divide 11296 and leave a remainder of 11 is 1.
What is the greatest common factor for 98?
The greatest common factor of a number is the largest positive integer that divides the number without leaving a remainder. For the number 98, the factors are 1, 2, 7, 14, 49, and 98. Therefore, the greatest common factor of 98 is 2, as it is the largest number that divides 98 without leaving a remainder.
Find the greatest number which divides 6168 2447 and 3118 leaving the same remainder in each case?
Well, honey, the greatest number that fits the bill is the difference between the numbers. So, 6168 - 2447 = 3721, and 3118 - 2447 = 671. The greatest number that divides all three and leaves the same remainder is the greatest common divisor of 3721 and 671, which is 671.
What is the greatest common factor of 10 15 and 30?
The greatest common factor of 10, 15, and 30 is 5.5
Find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively?
138. What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242 Find hcf of 276 and 1242: 1242 / 276 = 4 r 138 276 / 138 = 2 r 0 hcf of 276 and 1242 is 138. Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
What is the highest common factor of 130 and 165?
The highest common factor (HCF) of two numbers is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF of 130 and 165, you can use the Euclidean algorithm, which involves dividing the larger number by the smaller number and then using the remainder as the new divisor. By repeating this process, you will find that the HCF of 130 and 165 is 5.
What is the least common multiple of 20 and 34?
Expressing each number as the product of prime numbers can help a lot.First of all, we will find the greatest number which divides both number and then it is multiplied with other numbers in prime factorization of 34 and 20.Here the greatest number which divides both is 2.34: 2x17 and 20: 2x2x5L.C.M. = 2x17x2x5 = 34x10 = 340
