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The number is 25.

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Thus 25 is the greatest number that divides 364 414 and 539 with the same remainder (14) in each case.

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okay thanks

Q: What is the greatest number that divides 364 414 and 539 with the same remainder in each case?

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46.

742/105 = 7 remainder 7 1162/105 = 11 remainder 7

A factor of a number is any number which the original number can be divided by evenly. In this case, 29 divides by 7 to give 4 remainder 1. This remainder means that 29 does not divide evenly by 7. Thus 7 is not a factor of 29.

you first divide 17 by 3 and if you have a remainder don't try to to make it into a decimal now the answer should be 5 so the whole number would be 5 the remainder should be 2 so with 3 as the denominator make the remainder 2 in this case the numerator. the answer is 5 2/3 but if you have a problem where it divides evenly then you wont have to do any of the steps with the remainder the answer to the division would be a whole number by it self

No. When you divide a number by another number, let's say 26/4, you can't always get a perfect number. In this case, 6*4 is 24, and you have 2 "remainder", or 2 left over. The quotient is the whole answer, in this case 6 remainder 2. So the remainder is part of the quotient, but not the whole quotient itself.

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46.

360

742/105 = 7 remainder 7 1162/105 = 11 remainder 7

A factor of a number is any number that divides into the original number evenly. That is, it divides without leaving a fraction, decimal or remainder. In this case 34 divides by 4 to give 8 remainder 2. Therefore it does not divide evenly. Thus 4 is not a factor of 34.

This is a slight twist to the normal find the GCF of two numbers. In this case as a remainder of 7 is required, subtracting 7 from each number and then finding the GCF of the resulting numbers will solve the problem: 742 - 7 = 735 1162 - 7 = 1155 GCF of 1155 and 735 (using Euclid's method): 1155 / 735 = 1 r 420 735 / 420 = 1 r 315 420 / 315 = 1 r 105 315 / 105 = 3 r 0 GCF of 735 & 1155 is 105, thus 105 is the greatest number that will divide 742 and 1162 leaving a remainder of exactly 7 each time.

966 is the smallest thats all i know

A factor of a number is any number which the original number can be divided by evenly. In this case, 29 divides by 7 to give 4 remainder 1. This remainder means that 29 does not divide evenly by 7. Thus 7 is not a factor of 29.

If there is a remainder of 2 then number will divide 2 less than 110 (= 108) and 128 (=126) and be the largest such number. Thus need the hcf of 108 and 126: 108 = 22 x 33 126 = 2 x 32 x 7 hcf = 2 x 32 = 18 Thus 18 is the greatest number which will divide 110 and 128 with a remainder of 2 in each case.

The greatest such number is 1. If n is such a number, then 6168 = an + r 2447 = bn + r, and 3118 = cn + r for some integers a, b, c and r. This means that 6168 - 2447 = 3721 = (a-b)n 6168 - 3118 = 3050 = (a-c)n, and 3118 - 2447 = 671 = (c-b)n That is, n is the greatest common factor of 3721, 3050 and 671. But the GCF of these numbers is 1. Hence the answer.

The divisor of a number is a number which divides into that number. The least divisor of any number 1, so the least common divisor of 10 and 45 is also 1. Perhaps you meant "Least Common Multiple" (the smallest positive number which 10 and 45 divide without remainder) in which case LCM(10, 45) = 90 Or you meant "Highest Common Factor" (the largest positive number which divides into both 10 and 45 without remainder) in which case HCF(10, 45) = 5.

you first divide 17 by 3 and if you have a remainder don't try to to make it into a decimal now the answer should be 5 so the whole number would be 5 the remainder should be 2 so with 3 as the denominator make the remainder 2 in this case the numerator. the answer is 5 2/3 but if you have a problem where it divides evenly then you wont have to do any of the steps with the remainder the answer to the division would be a whole number by it self

Let the greatest number be 'x'. Then nx + 7 = 742 : nx = 735 And mx + 7 = 1162 :mx = 1155 The number required is the Greatest Common Factor of 735 and 1155. 735 expressed as the product of its prime factors = 3 x 5 x 7 x 7 1155 expressed as the product of its prime factors = 3 x 5 x 7 x 11 The GCF is 3 x 5 x 7 = 105