Sum of 1,2, ... , n is n*(n+1)/2
Here, n = 25 so sum = 25*26/2 = 325
The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25
The numbers are 25 and 17
Let's denote the two numbers as x and y. We know that x + y = 25 and xy = 156. By solving these two equations simultaneously, we can find the two numbers. One way to do this is by substituting y = 25 - x into the second equation, giving us x(25 - x) = 156. By solving this quadratic equation, we find that the two numbers are 12 and 13.
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
625
24 + 25 + 26 = 75
155
10 and 15.
The sum of the first 25 prime numbers is 1,060.
The two numbers are 25 and 14. 25+14=39 25-14=100
21 and 30 if you're only counting distinct factors. Add 25 and 32 if you're not.
34 + 25 = 59 34 - 25 = 9 The two numbers are therefore 34 and 25.
If the sum of 2 numbers is 25 and their product is 156, the 2 numbers would be 12 and 13.
The sum of the first 25 prime numbers is 1,060.
The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25
The numbers are 25 and 17
Let's denote the two numbers as x and y. We know that x + y = 25 and xy = 156. By solving these two equations simultaneously, we can find the two numbers. One way to do this is by substituting y = 25 - x into the second equation, giving us x(25 - x) = 156. By solving this quadratic equation, we find that the two numbers are 12 and 13.