Sum of 1,2, ... , n is n*(n+1)/2
Here, n = 25 so sum = 25*26/2 = 325
The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25
The numbers are 25 and 17
Let's denote the two numbers as x and y. We know that x + y = 25 and xy = 156. By solving these two equations simultaneously, we can find the two numbers. One way to do this is by substituting y = 25 - x into the second equation, giving us x(25 - x) = 156. By solving this quadratic equation, we find that the two numbers are 12 and 13.
625
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
24 + 25 + 26 = 75
155
10 and 15.
The sum of the first 25 prime numbers is 1,060.
The two numbers are 25 and 14. 25+14=39 25-14=100
21 and 30 if you're only counting distinct factors. Add 25 and 32 if you're not.
34 + 25 = 59 34 - 25 = 9 The two numbers are therefore 34 and 25.
If the sum of 2 numbers is 25 and their product is 156, the 2 numbers would be 12 and 13.
To find five numbers that have a mean of 25, their total sum must be 125, since the mean is calculated by dividing the sum by the number of values (125 ÷ 5 = 25). One possible set of numbers could be 20, 25, 25, 30, and 25. These numbers add up to 125, thus maintaining the required mean of 25.
The sum of the first 25 prime numbers is 1,060.
The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25
The numbers are 25 and 17