Sum of 1,2, ... , n is n*(n+1)/2
Here, n = 25 so sum = 25*26/2 = 325
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The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25
The numbers are 25 and 17
Let's denote the two numbers as x and y. We know that x + y = 25 and xy = 156. By solving these two equations simultaneously, we can find the two numbers. One way to do this is by substituting y = 25 - x into the second equation, giving us x(25 - x) = 156. By solving this quadratic equation, we find that the two numbers are 12 and 13.
625
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900