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Let x = 1st integer, since consecutive even integer differs by 2 then the 2nd integer = x + 2. So we have,

x + 4(x + 2) = 48

x + 4x + 8 = 48

5x = 40

x = 8 (1st integer)

Thus, the integers are 8 and 10.

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โˆ™ 2010-05-08 06:53:56
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A polynomial of degree zero is a constant term

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Q: Find two consecutive even integers such that the smaller number added to four times the larger gives a sum of 48?
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