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Q: Find two consecutive numbers with a product of 552?

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23x24.

I am thinking you know the numbers are 23 and 24 but wonder how to find it. The easiest way is if you have a calculator, is to take the square root of 552 and get 23.4 , so try 23 and 24 and it works! You know that x(x+1) should be about the same as xx and by taking the square root you find that (23.4)(23.4) is close to 552, so 23 times 24 will likely be what you want. Of course you can use algebra; let x be the smaller number, then x+1 is the other, so x(x+1) = 552 x2+x -552 = 0 If you try to factor : ( x + )(x - ) = 0 You need try to find two numbers whose product is 552 and whose difference is 1. but that the original problem!! You can use the quadratic formula, but the discriminant is 1+4*552 and you need to take the square root of that--- not hard, but harder than the first method.

The factors of 552 are: 1, 2, 3, 4, 6, 8, 12, 23, 24, 46, 69, 92, 138, 184, 276, 552.

There are no two conscutive numbers that ad up to be 552, for an odd and an even number, cannot equal an even, and consecutive numbers can't necessarily be decimals. However, there are two consecutive ODD numbers that add up to this number. This is because an odd plus an odd can equal an even. In a short way to do this, (NOT RECCOMENDED) You would divide this number by two: 552/2=276. Then you subtract one from 276, to get your first conecutive integer, and add one to 276 to get the second. The numbers would be: 275 and 277. These are consequitive because they go in an order. There are no other odd integers between them. Now for the long, more accurate way. (RECOMMENDED) First set up "Let" statements. Let X equal the smaller number. Let X = Smaller # For the second one, since you add 2 to get from one odd integer (as well as even integer) to the next, The larger # would equal X+2 Let X+2 = Larger # Since you have to add them together, it would be: X + X+2 = (The original total) 552 Then combine like terms to get: 2X + 2 = 552 Then solve. 552 - 2 = 550 2X = 550 is left. 550/2 = 275 X= 275 THAT IS NOT THE ANSWER!!! 275 is only equal to X, now plug it back into your "Let" Statements. Let X = Smaller # Becomes... Let 275 = Smaller # Now: Let X+2 = Larger Number Let 275 + 2 = Larger # 275 + 2 = 277. Same answers, but a more accurate method, depending if your teacher wants to see work. The two numbers are 275, and 277. Here is how to check it. Does 275 and 277 add up to 552? Yes it does. Hope that helps!!!

552 divide by 2 = 276

Related questions

23x24.

The numbers are 23 and 24.

If you mean consecutive numbers then they are 23*24 = 552

I am thinking you know the numbers are 23 and 24 but wonder how to find it. The easiest way is if you have a calculator, is to take the square root of 552 and get 23.4 , so try 23 and 24 and it works! You know that x(x+1) should be about the same as xx and by taking the square root you find that (23.4)(23.4) is close to 552, so 23 times 24 will likely be what you want. Of course you can use algebra; let x be the smaller number, then x+1 is the other, so x(x+1) = 552 x2+x -552 = 0 If you try to factor : ( x + )(x - ) = 0 You need try to find two numbers whose product is 552 and whose difference is 1. but that the original problem!! You can use the quadratic formula, but the discriminant is 1+4*552 and you need to take the square root of that--- not hard, but harder than the first method.

Let n be the lower number then the higher number is n + 1. n (n + 1 ) = 552 : n² + n - 552 = 0 Solving for the roots of a quadratic equation gives :- n = [-1 ± √(1 + 2208)] ÷ 2 = [-1 ± √2209] ÷ 2 = [-1 ± 47]÷ 2 Taking just the positive root gives n = -½ + 23½ = 23 The two consecutive numbers are therefore 23 and 24. Whilst this is a very accurate but complicated process a much quicker result can be achieved by taking the square root of 552 = 23.5 (approx). Two consecutive numbers producing 552 must lie either side of the square root. A simple multiplication will reveal that the numbers are 23 and 24.

552.

The numbers that go into both 552 and 42 are: 1, 2, 3, 6.

The smallest of these number is 225 and the largest is 552. So the range is 552-225 = 327.

The least common multiple of the numbers 46 and 24 is 552.

The factors of 552 are: 1, 2, 3, 4, 6, 8, 12, 23, 24, 46, 69, 92, 138, 184, 276, 552.

LCM(24, 23) = 552

The five on the left is ten times the five on the right.

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