Let n be the lower number then the higher number is n + 1.
n (n + 1 ) = 552 : n² + n - 552 = 0
Solving for the roots of a quadratic equation gives :-
n = [-1 ± √(1 + 2208)] ÷ 2 = [-1 ± √2209] ÷ 2 = [-1 ± 47]÷ 2
Taking just the positive root gives n = -½ + 23½ = 23
The two consecutive numbers are therefore 23 and 24.
Whilst this is a very accurate but complicated process a much quicker result can be achieved by taking the square root of 552 = 23.5 (approx). Two consecutive numbers producing 552 must lie either side of the square root. A simple multiplication will reveal that the numbers are 23 and 24.
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
3,5&7 3*5*7=105
x + y = 5xy=41 and 4 works. ■
Each one of them can be expressed as a sum of two primes.
You find the HCF of the two numbers, not their product. Example: 30 and 42 Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Select the common factors. 2 x 3 = 6, the HCF
33and 34
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
3,5&7 3*5*7=105
4 x 6 x 8 = 192
148
2 and 3.
Let the consecutive numbers be n and n+1, then n (n + 1) = 992 : n2 + n = 992 : n2 + n - 992 = 0 This equation factors : (n + 32)(n - 31) = 0 The only positive integer solution is when n - 31 = 0, then n = 31 so n + 1 = 32 The two consecutive numbers are 31 and 32.
777/3 = 259. So the numbers are 258, 259 and 260.
The nos. Are 8 and -8 Sum of the nos. 8+(-8)=0 Product of the nos. 8 × (-8) = -64
x + y = 5xy=41 and 4 works. ■
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
A composite number is an integer which is the product of two or more integers which greater than 1.