Avreage = Sum/number of values So 10 = sum/2 Multiply both sides by 2: 20 = sum
10 + 18 = 28 10 x 18 = 180
The sum of the first 10 even numbers is 110.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
8 and 28 + 2 = 108 x 2 = 16
They are: 14 and 4
10 and 2
4 and 6.
The prime factors of 30 are: 2 + 3 + 5 = 10
2 and 10. 2*10=20 2+10=12
Factors for 20 are: 1, 2, 4, 5, 10, 20 Prime Factors: 2, 5 sum of prime factors = 2 + 5 = 7
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
4nd 9.
21 and 32
The factors of 10 are 1, 2, 5, and 10. Among these, the pairs whose sum is 7 are 1 and 6, and 2 and 5. These pairs are factors of 10 as they divide evenly into 10 without leaving a remainder.
Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.
10 and 15.