6 and 4
Avreage = Sum/number of values So 10 = sum/2 Multiply both sides by 2: 20 = sum
The sum of the first 10 even numbers is 110.
The sum of their squares is 10.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
split 10 in two parts such that sum of their squares is 52. answer in full formula
They are: 14 and 4
4 and 6.
10 and 2
The prime factors of 30 are: 2 + 3 + 5 = 10
2 and 10. 2*10=20 2+10=12
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
Factors for 20 are: 1, 2, 4, 5, 10, 20 Prime Factors: 2, 5 sum of prime factors = 2 + 5 = 7
4nd 9.
21 and 32
The factors of 10 are 1, 2, 5, and 10. Among these, the pairs whose sum is 7 are 1 and 6, and 2 and 5. These pairs are factors of 10 as they divide evenly into 10 without leaving a remainder.
Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.
10 and 15.