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x + y =36 eq.1

x = 3y eq.2

Substitute value of x (eq.2) to equation 1:

3y + y = 36

4y = 36

y=9

x = 3y

x = 3(9)

x = 27

from equation 1: x + y =36

27 + 9 = 36

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Q: Find two numbers whose sum is 36 and such one is 3 times as large as the other?
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