The sum of the first thousand whole numbers can be calculated using the formula for the sum of an arithmetic series, which is n/2 * (first term + last term), where n is the number of terms. In this case, the first term is 1 and the last term is 1000. So, the sum would be 1000/2 * (1 + 1000) = 500 * 1001 = 500500.
The sum of the first five whole numbers is 10.
The sum of the first 14 in whole numbers is 91.
The sum of the cubes of the first 100 whole numbers is 25,502,500.
The sum of the first 10 odd whole numbers is 100.
The sum of the first 50 whole numbers is 1,225.
The sum of the first 1,000 whole numbers is 499,500.
The sum of the first 40 whole numbers is 780.
The sum of the first 30 even whole numbers is 30(31) or 930
The sum is 10,000.
We have to assume that you're talking about whole numbers. The sum is 5,050 .
The sum of the first 1,000 integers (whole numbers) is 499,500.
You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m