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Any odd integer can be represented as 2n+1, where n is any integer.
The integers, starting with one, always proceed as odd, even, odd, even, etc.
Therefore, a consecutive odd would be two more than the first.
So 2n+1, 2n+3, 2n+5, and 2n+7 summed to 336. Simple algebra gives n=40, and the four numbers as 81, 83, 85, and 87.
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Earn +20 ptsQ: Four consecutive odd integers whose sum is 336?
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4 consecutive integers whose sum is 336?
There are four consecutive odd integers: 81, 83, 85 and 87.
Find four consecutive odd integers whose sum is 336?
The integers are 81, 83, 85 and 87.
What are three consecutive odd integers whose sum is 336?
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
Three consecutive numbers that have a product of 336?
111 + 112 + 113 = 336
What is four - thirds of 252?
336
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