Capacitors resist change in voltage, so initially it will want to keep it's voltage (across it) the same. Depending on the configuration, the cap could initially behave as a short to attempt maintain that condition, or as a voltage source (if voltage was already present across the cap, for instance).
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It is the y-intercept.
initial - final / initial x 100
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If you are actually in your car, check the spedometer. That will tell you your instantaneous velocity; that is, distance traveled per second.If this is a calculus question and you are given the function of your position with respect to time, simply take the derivative of your function and evaluate your derivative at the time at which you would like to determine your instantaneous velocity.Alternatively and more unlikely, you can integrate your acceleration function and solve for your antiderivative based on an initial value given by the context of the problem.
The initial condition of a capacitor that has no energy stored is zero volts. The initial condition of an inductor that has no energy stored is zero amperes.
A capacitor in a washing machine helps to store and release electrical energy when needed. It is commonly used to provide the initial boost of power to the motor when the machine starts running and to help regulate voltage fluctuations during operation.
The initial condition is the voltage and/or current existing at the time a mathematical solution begins. Example: what happens when a resistor is connected across a capacitor? well, you say that at t=0 the resistor is connected, then after that the voltage across the capacitor is v0.exp(-t/RC), where v0 is the starting voltage, t is the time, R is the resistance and C is the capacitance. This simple solution needs only one initial condition which is the starting voltage v0 across the capacitor. Linear differential equations are common in electrical engineering and a complete solution of one (such as the example) always requires one or more initial conditions.
The run capacitor is used when the load is functional while the start capacitor is used to produce the initial torque to drive the load.
The shooting method is a method of reducing a boundary value problem to an initial value problem. You essentially take the first boundary condition as an initial point, and then 'create' a second condition stating the gradient of the function at the initial point and shoot/aim the function towards the second boundary condition at the end of the interval by solving the initial value problem you have made, and then adjust your gradient condition to get closer to the boundary condition until you're within an acceptable amount of error. Once within a decent degree of error, your solution to the initial value problem is the solution to the boundary value problem. Have attached PDF file I found which might explain it better than I have been able to here.
I suggest: - Take the derivative of the function - Find its initial value, which could be done with the initial value theorem That value is the slope of the original function.
The main purpose of a capacitor is to electrostatically store energy in an electric field. It is originally known as condenser.
the velocity function v= at + v(initial)
The word "initial" can function as either an adjective or a noun.
Gain is also taken as Laplace transform of output to Laplace transform of Input . for example voltage gain calculation , it is not necessary to make the energy will be zero in L and C ( if present in the given circuit). But in case of Transfer function to avoid the system dynamics , we have to make the inductor and capacitor energy will be zero as initial condition = 0
a capacitor and relay that gives the compressor an initial boost and then cuts out of the system by way of the relay.
A capacitor is a storage device like a battery it will however discharge at a rate of 63% for one RC time constant .so it is there to provide more initial force.