3 = 1 + 2 and 8 = 2+2+2 so 3 X 8 = (1+2)(2+2+2)= (1)(2 + 2+ 2) + (2)(2 + 2 + 2)=
1 X 2 + 1 X 2 + 1 X 2 + 2 X 2 + 2 X 2 + 2 X 2 , so you know the
multiplication facts 1 X 2 = 2 and 2 X 2 = 4 and know to add, you can work the problem.
3 X 8 = 2 + 2 + 2 + 4 + 4 + 4 .
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(1 x 3 ) x ( 2 X 4) = 24
3x8 with1s and 2s fact looks like this: =(2x8)+(1x8) =16+8 =24
6
2s + 16 = 4s - 6 Subtract 2s from both sides: 16 = 2s - 6 Add 6 to both sides: 22 = 2s divide both sides by 2: s = 11
100 2s for the hundreds digit of 200-30010 2s for the tens digit of 220-23010 2s for the ones digit of 200-300________________________________120 '2s'