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Q: How can you find the lenghth and width of triangle y?
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what- A triangle is formed by the intersection of the lines y = 2x + 4, y = -x – 2, and x = 1.Is the triangle equilateral, isosceles, or scalene Graph the lines on grid paper to find the vertices of the triangle?

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The sum of the length and width of a rectangle is 19 inches the length is 1 less than twice the width find the length and width of the rectangle?

Let x = length and y = width Then x + y = 19 Therefore x = 19 - y Also x = 2y - 1 (the length is 1 less than twice the width) So as x = x then 19 - y = 2y - 1 Therefore 3y = 20 which makes y = 6.666667 inches (width) and x = 19 - 6.666667 = 12.333333 inches (length) Twice the width would be 2 x 6.666667 = 13.3333333 inches and 1 less will be 12.3333333 inches (as above)


Triangle 2 is a reflection over the line x equals y of triangle 1?

x=y is the diagonal line which runs through 0,0 so all you have to do is reflect the triangle on the diagonal line. hop that helps :)


The length of a rectangle is three times its width If the perimeter of the rectangle is 48?

The perimeter of a rectangle is equal to 2*length + 2* width. In this case, we will say 2x + 2y = p = 48. Since the length is equal to 3 times the width, the equation now becomes p = 6*y + 2*y, or just p = 8y. Now since p =48, y must equal 6. And since the length is three times the width (y), the length is 18.


The length of a rectangle is 3 meters more than 2 times the width the area is 77 meters squared what is the length and width?

Let's call the lendth x and the width y x = 2y + 3 xy = 77 That is what is know in the trade as a simulataneous equation Because we have an x on its own lets substitute that equation into the second. (2y + 3)y = 77 2y2 + 3y = 77 2y2 + 3y -77 = 0 (2y - 11)(y + 7) = 0 y = 5.5 or -7 You don't get recangles with negative lengths so: y = 5.5 We can then substitute that into one of the equaitons to find x x = 2y + 3 x = 2*5.5 + 3 x = 14 So the length is 14 and the width is 5.5

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The sum of the length and width of a rectangle is 19 inches the length is 1 less than twice the width find the length and width of the rectangle?

Let x = length and y = width Then x + y = 19 Therefore x = 19 - y Also x = 2y - 1 (the length is 1 less than twice the width) So as x = x then 19 - y = 2y - 1 Therefore 3y = 20 which makes y = 6.666667 inches (width) and x = 19 - 6.666667 = 12.333333 inches (length) Twice the width would be 2 x 6.666667 = 13.3333333 inches and 1 less will be 12.3333333 inches (as above)