Make pairs, of one number from each end:
1 + 40 = 41
2 + 39 = 41
3 + 38 = 41
4 + 37 = 41
5 + 36 = 41
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19 + 22 = 41
20 + 21 = 41
You made pairs out of 40 numbers, so you have 20 pairs.
Each pair adds up to 41.
The sum is (20) x (41) = 820 .
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
The sum of whole numbers 1 through 30 is 465.
The sum of the first five whole numbers is 10.
What to whole numbers have a sum of 12 and quotient of 3?
The three consecutive whole numbers you are looking for are 1, 2, and 3. The sum of the first two numbers, 1 + 2 = 3.
You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m
you can use whole numbers
The sum of two numbers is a whole number if both of the numbers are whole numbers, or if the sum of two fractions can be simplified to a whole number.
5050
The sum of the first 14 in whole numbers is 91.
All the odd numbers.
The total of all of the numbers from 1 to 99 is 4950.
It is not possible to express something as a sum of whole numbers with no common factor. All whole numbers have at least 1 as a common factor.
Add them up.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
It is called a whole consecutive number.
210