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Oh, dude, you can totally place the tiles 1-9 in a 3x3 square grid so each row, column, and diagonal adds up to the same sum. Then you can just plop the 10th tile in the center to make sure everything balances out. It's like a Sudoku puzzle, but with numbers instead of letters. Easy peasy!
To place tiles 1-10 so each side has the same sum, you would need to arrange them in a specific way to ensure balance. One possible solution is to place tiles 1, 2, 4, and 7 on one side, and tiles 3, 5, 6, 8, 9, and 10 on the other side. This arrangement ensures that both sides have a sum of 14. This solution follows the concept of creating balanced equations to achieve equal sums on both sides.
Oh honey, that's a classic math puzzle. You just need to arrange the numbers in a way that the sum of each side is the same. In this case, you can place the numbers 1, 2, 3, and 4 in the corners, with the numbers 6, 8, 9, and 10 in the center, and finally the numbers 5 and 7 on the remaining sides. Voila, all sides will have the same sum!
5 x 8 = 40 tiles 5 on one side and 8 on the other side
Lets do length and width in terms of tiles. The length is 6m/0.2m/tile 30 tiles and the width is 5m/0.2m/tile 25 tiles. Then the area is l X w 30 tiles X 25 tiles 750 square tiles. Since each tile is square, 750 tiles.
Each side of a regular hexagon is the same as its radius - in this case 31 inches.
One way is: ...1862...2573...3941...
8 of them.