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How can you use 5 2s to equal 26?
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
How do you make 42 using five 2s?
22 + 22 - 2 = 42
How can you use five 2s to get 42?
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
How do you get 11 with five 2s?
(2x2x2)/2 + 2
How can you make five 2s equal five?
2 + 2 + 2 + 2/2 = 6 - 1 = 5
How can you use 5 2s to equal 26?
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
How do you make 42 using five 2s?
22 + 22 - 2 = 42
How many 2s go into 52?
26
How can you use five 2s to get 42?
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
How do you get 11 with five 2s?
(2x2x2)/2 + 2
How do you factor 4s2-9?
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
Is it possible to get 10 using 3 2s?
no.
How do you make the number 9 with five 2s only?
You can make the number 9 using five 2s by adding them together like this: 2 + 2 + 2 + 2 + 2 = 10, then subtracting 2: 10 - 2 = 8, then dividing by the remaining 2: 8 ÷ 2 = 4, and finally adding two more 2s: 4 + 2 + 2 = 9.
How can you make five 2s equal five?
2 + 2 + 2 + 2/2 = 6 - 1 = 5
How can you use five 2s to equal 9?
2x2x2+2/2 = 9
Can you make 9 using only four 2s?
Yes
How do you make the number 11 with five 2s only?
22/2 *2/2
