(22/2+2)x2
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
22 + 22 - 2 = 42
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
(2x2x2)/2 + 2
Yes
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
You can use five 2s to make 26 by using the following mathematical expression: ( (2 + 2) \times (2 + 2) + 2 ). This simplifies to ( 4 \times 4 + 2 = 16 + 2 = 18 ), which does not yield 26. Instead, the correct expression would be ( 22 + 2 + 2 ). However, a valid approach is to use ( 22 = 2 \times 10 + 2 ), making it possible to achieve 26 using five 2s.
22 + 22 - 2 = 42
26
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
(2x2x2)/2 + 2
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
no.
You can make the number 9 using five 2s by adding them together like this: 2 + 2 + 2 + 2 + 2 = 10, then subtracting 2: 10 - 2 = 8, then dividing by the remaining 2: 8 ÷ 2 = 4, and finally adding two more 2s: 4 + 2 + 2 = 9.
2x2x2+2/2 = 9
Yes
Well, honey, if you want to make five 2s equal five, all you gotta do is write it as 2 + 2 + 2/2 = 5. Simple math, darling. Just divide one of those pesky 2s by 2 and voila, you've got yourself a nice little equation that adds up to 5.