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How can you use 5 2s to equal 26?
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
How do you make 42 using five 2s?
22 + 22 - 2 = 42
How can you use five 2s to get 42?
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
How do you get 11 with five 2s?
(2x2x2)/2 + 2
Can you make 9 using only four 2s?
Yes
How can you use 5 2s to equal 26?
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
How do you use 5 twos to make 26?
You can use five 2s to make 26 by using the following mathematical expression: ( (2 + 2) \times (2 + 2) + 2 ). This simplifies to ( 4 \times 4 + 2 = 16 + 2 = 18 ), which does not yield 26. Instead, the correct expression would be ( 22 + 2 + 2 ). However, a valid approach is to use ( 22 = 2 \times 10 + 2 ), making it possible to achieve 26 using five 2s.
How do you make 42 using five 2s?
22 + 22 - 2 = 42
How many 2s go into 52?
26
How can you use five 2s to get 42?
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
How do you get 11 with five 2s?
(2x2x2)/2 + 2
How do you factor 4s2-9?
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
Is it possible to get 10 using 3 2s?
no.
How do you make the number 9 with five 2s only?
You can make the number 9 using five 2s by adding them together like this: 2 + 2 + 2 + 2 + 2 = 10, then subtracting 2: 10 - 2 = 8, then dividing by the remaining 2: 8 ÷ 2 = 4, and finally adding two more 2s: 4 + 2 + 2 = 9.
How can you use five 2s to equal 9?
2x2x2+2/2 = 9
Can you make 9 using only four 2s?
Yes
How can you make five 2s equal five?
Well, honey, if you want to make five 2s equal five, all you gotta do is write it as 2 + 2 + 2/2 = 5. Simple math, darling. Just divide one of those pesky 2s by 2 and voila, you've got yourself a nice little equation that adds up to 5.
