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(2x2x2)/2 + 2


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Q: How do you get 11 with five 2s?
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Related questions

How do you make the number 11 with five 2s only?

22/2 *2/2


How can you use five 2s to get 42?

Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42


How do you simplify 7-2s plus 4 plus 5s?

7-2s+4+5s ..... Okay first you combine like terms(add the like terms)..so its going to be 11+3s I did 7+4=11 then -2s+5s=3s So the answer can be 11+3s or 3s+11


2r plus 2s equals 50 and 2r minus s equals 17?

2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17


What is the answer to 2s plus 16 equals 4s - 6?

2s + 16 = 4s - 6 Subtract 2s from both sides: 16 = 2s - 6 Add 6 to both sides: 22 = 2s divide both sides by 2: s = 11


How do you get 26 using five 2s?

(22/2+2)x2


How can you make five 2s equal five?

2 + 2 + 2 + 2/2 = 6 - 1 = 5


How do you make 42 using five 2s?

22 + 22 - 2 = 42


How can you use five 2s to equal 9?

2x2x2+2/2 = 9


How can you use 5 2s to equal 26?

You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26


The difference between two numbers is 11 Twice the smaller number plus three times the larger number is 123?

L = S + 11; 2S + 3(S + 11) = 123, ie 2S + 3S + 33 = 123ie 5S = 90 ie S = 18 and L = 29


What is the Number of orbitals in nitrogen?

Nitrogen has five electron orbitals: one 2s orbital and three 2p orbitals.