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How do i solve twice a number minus three times the number is equal to one third the number plus fourteen?
Write the statement as an algebraic equation. Then solve the equation.
Twice a number: 2x
Three times the number: 3x
One third the number: x/3
In your question, you said: 2x - 3x = x/3 + 14
Multiply each side by 3 ==> 6x - 9x = x + 42
Combine the terms on the left side ==> -3x = x + 42
Subtract 'x' from each side==> -4x = 42
Divide each side by -4 ==> x = 42/(-4) = -21/2
x = -10.5
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