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Write the statement as an algebraic equation. Then solve the equation.

Twice a number: 2x

Three times the number: 3x

One third the number: x/3

In your question, you said: 2x - 3x = x/3 + 14

Multiply each side by 3 ==> 6x - 9x = x + 42

Combine the terms on the left side ==> -3x = x + 42

Subtract 'x' from each side==> -4x = 42

Divide each side by -4 ==> x = 42/(-4) = -21/2

x = -10.5

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Q: How do i solve twice a number minus three times the number is equal to one third the number plus fourteen?
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