when you're given a point and a slope and you're trying to figure out an equation you use the point-slope equation: y-y1=m(x-x1)
x1 and y1 are the x and y coordinates of the point given and m is the slope
example: slope is 5 point (4/5, 6)
plug them in to the equation
y-6=5(x-4/5)
y-6=5x-4 distribute 5
y=5x-4+6 add 6 to both sides
y=5x+2 combine like terms
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Use point-slope formula
Slope: -3 Point: (4, -5) Equation: y = -3x+7
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
y - y1 = m (x - x1) If your point was (5,4) and your slope was 3, then the equation would look like this: y - 4 = 3 (x - 5) Then you would use distributive property to solve from there...but continueing to solve would not be point-slope form... y-4=3(x-5) would be your complete answer for a question asking to write an equation in point-slope form.
That will depend on the value of the slope which has not been given.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
If you solve such an equation for "y", you get an equation in the slope-intercept form.
If the algebraic equation is linear, in the form y = mx + b, the slope is simply m; the difference in y of any 2 points divided by the difference in x of those points (rise over run). If the equation is non-linear, the slope is the first derivative of that equation, from calculus. You woul need to know calculus to solve in this case. The slope will vary from point to point, unlike the linear case, where slope is constant.
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
This is easy using the point-slope formula of a line: y - y1 = m(x - x1) So, knowing that the slope m = 3, and x1 = -1, and y1 = 5, just plug these values into the equation above, then solve for y to get the equation in standard slope-intercept form.
35
no it is different
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14