Point: (-6, -2) Slope: 5 Equation: y = 5x+28
The equation for a line of slope m going through point (Xo, Yo) is given by: y - Yo = m(x - Xo) So for line of slope 2 going through (1, 9) the equation is: y - 9 = 2(x - 1) ⇒ y = 2x + 7
(6,2)
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Use point-slope formula
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
write an equation that has a slope 7 and passes through the point (2,17)
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Point: (2, 3) Slope: 2 Equation: y = 2x -1
Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)
Point: (-3, 4) Slope: 2 Equation: y-4 = 2(x--3) => y = 2x+10
Points: (-3, -2) and (1, 2) Slope: 1 Equation: y = x+1
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90