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Slope intercept form:

y = mx + b

(where y = y, m = slope, x = x, and b = y-intercept)

The equation is written as "y = " so that it is easier for you to plug it into a graph.

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Here is an example:

-Find the equation of the straight line that has a slope m = 4 and passes through the point (-1,-6).

--> You are given the value of the slope. In this example the slope or m = 4.

--> They gave you a point on the line too, so that means that they gave you an x-value and a y-value for this line. The x = -1 and y = -6.

So far you have the y, m, and x. So what's the only thing you are missing from the slope-intercept equation? Remember the equation is y = mx + b

So the only thing you don't have so far is a value for is b (which gives me the y-intercept).

Now all you need to do is plug in what they gave for the slope and the x and y from this particular point, and then solve for b: y = mx + b

(-6) = (4)(-1) + b

-6 = -4 + b

-2 = b

You can then write the equation out! = y = 4x -2

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x - 3y = 6

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noelyyyy

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Q: How do write an a equation for a slope intercept form?
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