Assuming you know c (not Arc ZX) and m then the formula would be:
r = (m² + ¼c²)/2m if all you need to know is the radius of an arc, and you have the base length and rise, the formula would be: radius = (rise2 + 1/2 width2) / 2 x rise
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multiply the chord length and radius and divide by 2
To find the radius of the circle, we can use the Pythagorean theorem. The chord divides the circle into two equal parts, each forming a right triangle with the radius. The radius, the distance from the center to the chord, and half the length of the chord form a right triangle. Using the Pythagorean theorem, we have (radius)^2 = (distance from center)^2 + (1/2 * chord length)^2. Substituting in the given values, we get (radius)^2 = 8^2 - (1/2 * 4.2)^2. Solving for the radius gives us a radius of approximately 7.48 cm.
longest chord = diameter y = longest chord y = diameter radius = 1/2 diameter therefore, radius = 1/2y
The radial length equals the chord length at a central angle of 60 degrees.
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).