Draw any finite line. Write C near one end; write D near the other end. You now have a line segment and have named it CD.
Median of a trapezoid is a line segment found on the midpoint of the legs of a trapezoid. It is also known as mid-line or mid-segment. Its basic formula is AB + CD divided by 2.
3
Draw a number line (l) and mark the points O, A, B and C such that OA = AB = BC = 1Draw CD ⊥ l, such that CD = 1 units.Join OCIn right ΔOCD,OD2 = OC2 + CD2Taking O as centre and D as radius, draw an arc which cuts l in FNow, draw EF ⊥ l, such that EF = 1 unitsJoin OE'In right ΔOEF,OE2 = OF2 + EF2Taking O as centre and OE as radius, draw an arc which cuts l in HNow, draw GH ⊥ l, such that GH = 1 unitsJoin OGIn right ΔOGH,Taking O as centre and OG as radius, draw an arc which cuts l in J.Now, draw IJ ⊥ l, such that IJ = 1 unitsJoin OI,In right ΔOIJ,Taking O as centre and OI as radius, draw an arc which cuts l in L.The point L represents on the number line.
a b c
Ab and Ba are the same line because there are no endpoints to a line. Therefore, you can reverse the order of the letters. So, Cd and Dc are not the same ray because the first letter is the endpoint. So on ray Cd, point C is the endpoint and d is a point on the line coming from the endpoint. On ray Dc, D is the endpoint.
To draw and label perpendicular line segments, start by drawing a horizontal line segment using a ruler. Next, use a protractor to measure a 90-degree angle from one endpoint of the segment, and draw a vertical line segment from that point. Label the endpoints of each line segment with letters (e.g., A, B for the horizontal segment and C, D for the vertical segment). Finally, clearly indicate that the segments AB and CD are perpendicular by marking the right angle at their intersection.
It is easiest to draw it using two right angled triangles.Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
Yes, it doesn't matter which end you start with when naming a line segment.
A line segment, such as segment CD, is a part of a line that connects two distinct endpoints, C and D. It has a definite length, measured as the distance between these two points. In geometry, it is often used to illustrate basic concepts of distance, measurement, and the properties of shapes. The notation for segment CD is typically written as ( \overline{CD} ).
== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units
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CD and DC
Yes, line segments CD and dc are considered the same because they represent the same line segment regardless of the order of the endpoints. In geometry, the notation for a line segment does not depend on the sequence of the letters; both CD and dc denote the same path between points C and D.
To construct segment EF with a length equal to the sum of segments AB (5) and CD (8), first draw segment AB measuring 5 units. Then, from one endpoint of segment AB, use a compass to measure out 8 units to create segment CD. Finally, connect the endpoint of segment CD to the endpoint of segment AB to form segment EF, which will measure 13 units in total.
The symbol used to denote parallel sides is "∥". For example, if line segment AB is parallel to line segment CD, it can be expressed as AB ∥ CD. This notation is commonly used in geometry to indicate that two lines or line segments will never intersect, regardless of their length.
Median of a trapezoid is a line segment found on the midpoint of the legs of a trapezoid. It is also known as mid-line or mid-segment. Its basic formula is AB + CD divided by 2.
Let us say the line segment is AB. Then take a compass and spread it so that the distance between the needle around which the compass rotates and the pencil at the other end is a little over half the length of AB. Place the needle of the compass on A and draw small arcs above and below the line AB. Without altering anything on the compass, place the needle on B and draw small arcs as before above and below the line AB such that these arcs intersect the older arcs. Now join the two intersection points of the arcs and call this line CD. CD is the right bisector of AB A----------------|----------------B