Pattern recognition
This site no longer allows me to enter subscripts so I will use brackets: a(n) to indicate the nth term.a(n) = a(1) + (n-1)*d where d is the common difference between the terms of the arithmetic sequence.Therefore, d = [a(n) - a(1)]/(n-1)Then, the appropriate arithmetic series isS(n) = 1/2*n[2*a(1) + (n-1)*d] where all the terms on the right hand side are known.
You replace each variable by its value. Then you do the indicated calculations.
When quantities in a given sequence increase or decrease by a common difference,it is called to be in arithmetic progression.
Substitute the given value for the argument of the function.
To evaluate an expression is nothing but to operate the given expression according to the operators given in the expression if it is evaluable i.e, it could be convertable.
This site no longer allows me to enter subscripts so I will use brackets: a(n) to indicate the nth term.a(n) = a(1) + (n-1)*d where d is the common difference between the terms of the arithmetic sequence.Therefore, d = [a(n) - a(1)]/(n-1)Then, the appropriate arithmetic series isS(n) = 1/2*n[2*a(1) + (n-1)*d] where all the terms on the right hand side are known.
You replace each variable by its value. Then you do the indicated calculations.
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When quantities in a given sequence increase or decrease by a common difference,it is called to be in arithmetic progression.
-161.
A variable
Given an arithmetic sequence whose first term is a, last term is l and common difference is d is:The series of partial sums, Sn, is given bySn = 1/2*n*(a + l) = 1/2*n*[2a + (n-1)*d]
Substitute the given value for the argument of the function.
Never. The geometric return is always lower than the arithmetic average returns unless the returns for the given set of data are all the same.
To evaluate an expression is nothing but to operate the given expression according to the operators given in the expression if it is evaluable i.e, it could be convertable.
evaluate the process of effective communication.
The given number is the same as 65 and in scientific notation it is 6.5*10^1