2(8y + 1)
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4(y + 2)(y + 2)
4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2
It is: 2(4x+5)
4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2
You factor out 5 from the expression (10+5p). You get 2(5+p).