Q: Factor the expression 2 plus 16y?

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4(y + 2)(y + 2)

4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2

It is: 2(4x+5)

4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2

You factor out 5 from the expression (10+5p). You get 2(5+p).

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x^2 plus 16y?

4(y + 2)(y + 2)

4(y + 2)(y + 2)

4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2

4(3y + 2)(7y - 6)

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It is: 2(4x+5)

4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2

2(x+3)

(y + 8)(y - 2)

y + y + 2 = 182y + 2 = 182y = 16y = 8whew !

(y + 8)(y - 2)