You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
2x2 + 7x - 15 = (2x - 3)(x + 5)
What is the solution set of 2x2 + x = 15
If you mean: 2x2+11x+15 then it is (2x+5)(x+3) when factored
x2 + 8x + 15 = (x + 3)(x + 5)
2x2+13x+15 = (2x+3)(x+5)
-2(2x^4 - 13x^3 + 15)
It cannot be factored because the discriminant of b2-4ac is less than zero.
2x^2 + 13x + 15 factored means that the two numbers must multiply to the constant (15) and add to equal the coefficient on the X (13). So it becomes: (2x + 3) (x + 5). If expanded, 2x*5 = 10x and 3 * x = 3x which add to 13x. And 5 * 3 = 15
13x + 15 = 11x - 5 2x = -20 x = -10
2x2 + 11x + 15 = (x + 3)(2x + 5).
Divide all terms by 2 it is then x2-15+56 = (x-7)(x-8) when factored
7x-5+2x=3-4x+12 7x+2x-5=3+12-4x 9x-5=15-4x 9x+4x-5=15-4x+4x 13x-5=15 13x-5+5=15+5 13x=20 13x/13=20/13 x=20/13
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
-13
2x2 + 7x - 15 = (2x - 3)(x + 5)
The highest common factor of 15 and 45 is 15