Well, darling, if we're talking math, P squared plus P squared equals 2P squared. It's as simple as that. So, next time you're trying to impress someone with your algebra skills, just remember this little gem.
2p + 11p + 5 = 13p + 5 which does not factor. If the expression had been 2p2 + 11p + 5 then this can be factored, 2p2 + 11p + 5 = (2p + 1)(p + 5)
p^2 x p^2 = p^4 p^2 + p^2 = 2p^2
When (p = 3),2 p2 = 2 (3)2 = 2 (9) = 18 .(2p)2 = 4 p2 = 4 (3)2 = 4 (9) = 36
It equals 2p because p+p=2p.
3p2-2p-5 = (3p-5)(p+1) when factored
-2p squared
(3q + 2p)(9q + 7p)
p2 = 2p + 15 p2 - 2p - 15 = 0 (p - 5)*(p + 3) = 0 so p - 5 = 0 or p + 3 = 0 so p = 5 or p = -3
Well, darling, if we're talking math, P squared plus P squared equals 2P squared. It's as simple as that. So, next time you're trying to impress someone with your algebra skills, just remember this little gem.
2p + 11p + 5 = 13p + 5 which does not factor. If the expression had been 2p2 + 11p + 5 then this can be factored, 2p2 + 11p + 5 = (2p + 1)(p + 5)
p^2 - 2p - 3 = 0 p^2 - 2p = 3 halve the linear term (-2), square it and add it to both sides p^2 - 2p + 1 = 3 + 1 factor left, gather terms right (p - 1)^2 = 4 (p - 1)^2 - 4 = 0 (1,-4) are the vector points of this parabola You can factor to solve for p (p + 1)(P - 3) p = - 1 p = 3
p^2 x p^2 = p^4 p^2 + p^2 = 2p^2
When (p = 3),2 p2 = 2 (3)2 = 2 (9) = 18 .(2p)2 = 4 p2 = 4 (3)2 = 4 (9) = 36
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (7 plus or minus the square root of 145) divided by 16. p = 1.1900996611745185 p = -0.3150996611745185
It equals 2p because p+p=2p.
p + 22q2