You could factor this as a difference of squares, but because 8 is not a perfect square, you would wind up with radicals in your answer:
x2 - 8
= (x + √8)(x - √8)
= (x + 2√2)(x - 2√2)
(x + 1)(x - 8)
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
(3x + 8)(3x - 8)
(x + 2)(x - 4)
(7x + 8)(7x - 9)
It is: (2x+3)(3x-8) when factored
To factor the quadratic expression (x^2 + 7x - 8), we need to find two numbers that multiply to (-8) (the constant term) and add to (7) (the coefficient of the linear term). The numbers (8) and (-1) satisfy these conditions. Thus, we can factor the expression as ((x + 8)(x - 1)).
2(x^2 - 8)
(b + 8)(b - 1)
(2x - 1)(5x + 8)
You don't! There are no common factors.
y2-y-72 is an algebraic expression that can be factored as: (y+8)(y-9)