x2 - 14x + 49(x - 7) (x - 7)
-47
first you must factor the equation... (x - 7)(x + 2) x = 7 and -2 Your factors are 7 and -2
-167
y = x2 - 7x + 8 y = -x2 + 9x - 6 subtract the 2nd from the 1st equation 0 = 2x2 - 16x + 14 simplify 0 = x2 - 8x + 7 factor it, since 7 = (-1)(-7) and -1 - 7 = -8 0 = (x - 1)(x - 7) let each factor equal to zero x - 1 = 0 or x - 7 = 0 solve for x thus, x = 1 and x = 7. Chose one of the equation and substitute x with 1, and 7 to find the corresponding y-values. y = x2 - 7x + 8 y = (1)2 - 7(1) + 8 = 1 - 7 + 8 = 2; (1, 2) intersection point y = (7)2 - 7(7) + 8 = 49 - 49 + 8 = 8; (7, 8) intersection point
x2-49 = (x-7)(x+7)
7(x2 + 7)
x2 - 14x + 49(x - 7) (x - 7)
(x - 7)(x - 7)
(x + 7)(x + 7)
x2+2x-63 = (x-7)(x+9) when factored
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
x4 + x2 - 42 Let x2 = t, so that x4 = t2 t2 + t - 42 since -42 = 7(-6) and 7 + (-6) = 1, then t2 + t - 42 = (t - 6)(t + 7) = (x2 - 6)(x2 + 7) By replacing t with x2. So we have, x4 + x2 - 42 = (x2 - 6)(x2 + 7) = [x2 - (square root of 6)2](x2 + 7) = (x - sq. root of 6 )(x + sq. root of 6)(x2 + 7)
(x - 7)(x - 3)
(x + 6) (x - 7)
(x - 3)(x + 7)
The GCF is 7. Divide both terms by 7. 7(x2 - 10)