(y-10)*(y+10)
since y2 -100 is a pattern known as the difference of squares. This simply means both terms are perfect squares and you are subtracting them.
In general if you have a2 -b2 this factors as (a+b)(a-b). The reason this works is that the plus and minus signs make the middle terms cancel out. That is to say, when you multiply it out you have a2 + ab-ba-b2 and since -ba+ab=0 we have the desired result.
Although this works for all real numbers, sometimes we multiply "other things" where
AB does not equal BA and then it won't work.
(y - 8)(y - 2)
35
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
(x^2 - y^2) / (x - y) Apply the difference of squares formula: (x + y)(x - y) / (x - y) Assuming x is not equal to y, we can cancel terms leaving x + y When x = y, the denominator becomes 0, and the equation gives no information.
3xy + 3y2 = 3y (x + y)
y² - y - 6 = (y + 2)(y - 3)
There are no rational factors.
it is (x-y)(x-y) :)
The factoring is as follows: x2 - y2 = (x + y) * (x - y)
(y - 2)(y - 7)
x^2 - y^2 - 4 is in its simplest form.
4(y - 3)(y + 3)
(3y - 5)(y + 5)
y² - y all depends on the value of y. If you want to factor the expression, then we have y(y - 1)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
(x - y)(x + y)
(2y - 5)(y - 2)