The area of a triangle does not provide enough information to determine its dimensions.
The square of the length of the base plus the square of the length of the height will equal the square of the length of the hypotenuse of your right triangle, per Pythagoras. Square the hypotenuse, subtract the square of the height, and then find the positive square root of that and you'll have the base of your right triangle.
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
The area of a triangle equals half of the length of its base times its height.Area of a triangle with base of 16 units and height of 14 units is 112 square units.
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
Depends on the figure: square/rectangle is length time height Triangle is .5base times height Circle is pi r^2
The square of the length of the base plus the square of the length of the height will equal the square of the length of the hypotenuse of your right triangle, per Pythagoras. Square the hypotenuse, subtract the square of the height, and then find the positive square root of that and you'll have the base of your right triangle.
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
To find the altitude or height of an equilateral triangle, take one-half of the length of a side of the triangle and multiple by "square root" of 3. So, if for example, the side has length 10, the height = 5 Square root of 3.
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.
You do not indicate if the given area is the total area of the square and the triangle. Or whether they are equal values.
-- For both shapes, multiply the length of the base by the height of the figure. -- For the triangle only, take 1/2 of the result. -- Now you have the area of each shape.
Figure width X 1/2 length of the triangle to get Square feet.
Triangle Area = ½base × height Square Area = length of side to the power of 2 Rectangle Area = breadth × height Parallelogram Area = breadth × height Circle Area = πrto the power of 2
7.5 square units
The first is clearly not a suitable triangle.
it depends on what shape it is. square: perimenter/4 is one side's length. triangle: perminter/3 rectangle: perimeter/height = length or perimeter/length = height