One other angle or the length of one other side must also be known.
The length of the hypotenuse, alone, is not sufficient to determine the area of a triangle.
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2
The Pythagorean Theorem is a statement about triangles containing a right angle. The Pythagorean Theorem states that:"The area of the square built upon the hypotenuse of a right triangle is equal to the sum of the areas of the squares upon the remaining sides."
Using the quadratic equation formula and Pythagoras' theorem the length of the hypotenuse works out as 67.5 mm which is 6.75 cm
Area of a right angle triangle is: 0.5*base*height
The hypotenuse is the longest side of a right angle triangle The area of a circle is pi*radius2
The area of a right angle that has a base of 3 inches height of 4 inches and a 5 inch hypotenuse is: 6 square inches.
Knowing just the length of the base you can not work out the area. You need the height and the base or the length of the hypotenuse in order to work out the area.
I assume the question refers to a right angled triangle, since a rigt angle, by itself, cannot have an area. There are three possible answers - depending upon which of the sides are "a" and "b". Case 1: The right angle is between the sides "a" and "b". The area is 0.5*a*b Case 2: The side "a" is opposite the right angle (the hypotenuse). Then the third side, c is sqrt(a2-b2). The area is 0.5*b*c Case 3: The side "b" is opposite the right angle (the hypotenuse). Then the third side, c is sqrt(b2-a2). The area is 0.5*a*c
Hmmm. the triangle you describe is HALF of a rectangle...
If it's a right angle triangle then the dimensions of one of its sides is also needed
It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
There is no right triangle on the right! (Ignore the length of the hypotenuse of a right triangle.) if you have the length of the two legs (base and the upright side): (base x upright) ÷ 2 = area of the right angle triangle.
A right triangle with a hypotenuse of 10m and a base of 5m has an area of: 21.65m2
Not enough information has been given to solve this problem.
In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).
The length of the hypotenuse is not sufficient information. You need the length of one of the legs or one of the acute angles. Or some other information that will enable you to derive that.