If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
This requires trigonometry If theta is the angle from the center of the circle to the edges of the chord, then chord length = 2Rsin (theta/2)
False
Radius
a chord is a line between two points on the circle the radius is a line from the center to the circle
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
Angles are like 90˚ and 180˚. A circle is a circle.... "O" <=====this.. So, the only relationship I can guess is that angles can be created inside and outside of the circle. One such example can be a chord and a diameter touching each other at one end. Or a chord and a radius.. Or a radius and another radius. Hope this helps.
Then the radius bisects the chord.
No, but the diameter of a circle is its largest chord
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
A chord is when two points in a circle are connected by segment. A diameter is a chord, but not a radius. The radius is not a complete segment in the circle
This requires trigonometry If theta is the angle from the center of the circle to the edges of the chord, then chord length = 2Rsin (theta/2)
Bisects
Perpendicular.
No, a radius connects the center of a circle the a point on the outside, a chord connects to points on the outside of the circle. Thanks for asking on
Bisects that chord