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Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
what is the distance between -2 and -1 1/2?
What is the distance between (4, -2) and (-1,6)?
What is the distance between 1 and -3 on a number line?
4
Find the distance between the following pairs of points Round your answer to the nearest tenth 4 and -3 and the second is 2 and 4?
P1 = (4, -3)P2 = (2, 4)(Distance)2 = (delta-x)2 + (delta-y)2(Distance)2 = (4 - 2)2 + (-3 - 4)2 = (2)2 + (-7)2 = 4 + 49 = 53Distance = sqrt(53) = 7.3 (rounded)
What is the distance between the points -2 5 and 3 -4?
In order to find the distance between two coordinates, you first need to find the difference between the x and y coordinates. In this case, the difference between the x coordinates is 3-(-2) = 5. The difference between the y coordinates is -4-5 = -9. To find the distance you add up the squares of these differences then find the square root. 52 = 25. -92 = 81. 25+81 = 106. Thus the distance is the square root of 106, or approximately 10.296
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between -2 4 and 1 -2?
What is the distance between (4, -2) and (-1,6)?
How can you find the distance between two numbers on a number line?
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
What is the distance between 4 -2 and -1 6?
What is the distance between (4, -2) and (-1,6)?
Find the distance between 8 -4 and 2 15?
(8-2)2+(-4-15)2 = 397 and the square root of this is the distance which is 19.925 rounded to 3 decimal places
what is the distance between -2 and -1 1/2?
What is the distance between (4, -2) and (-1,6)?
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between 1 and -3 on a number line?
4
Find the distance between the points 4 6 and 4 6?
Since they are the same point, the distance between them is 0.
Find the distance between the following pairs of points Round your answer to the nearest tenth 4 and -3 and the second is 2 and 4?
P1 = (4, -3)P2 = (2, 4)(Distance)2 = (delta-x)2 + (delta-y)2(Distance)2 = (4 - 2)2 + (-3 - 4)2 = (2)2 + (-7)2 = 4 + 49 = 53Distance = sqrt(53) = 7.3 (rounded)
What is the distance between the points -2 5 and 3 -4?
In order to find the distance between two coordinates, you first need to find the difference between the x and y coordinates. In this case, the difference between the x coordinates is 3-(-2) = 5. The difference between the y coordinates is -4-5 = -9. To find the distance you add up the squares of these differences then find the square root. 52 = 25. -92 = 81. 25+81 = 106. Thus the distance is the square root of 106, or approximately 10.296
Find the distance between the points -2 2 and 2 -2?
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (4) and a vertical distance y2-y1 (4). The square root of the squares is sqrt [42 + 42] = sqrt [32] = approx 5.66
