if you mean a right triangle then the formula is a squared + b squared = c squared. a and b are the legs and c is the hypotunese. the legs are the smallest number then the hypotenese.
An example is a=3 , b= ? and c =5
use the formula : a squared + b squared = c squared
3 squared + b squared = 5 squared
9 + b squared = 25
-9 - 9
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b squared = 16
Then you have to take the squared root of 16 which is 4 and 4 is b squared.
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2
If it's a right angle triangle then the other leg will also be 13 units in length and use Pythagoras' theorem if you need to find the length of the hypotenuse.
This is impossible. A leg cannot be greater than the hypotenuse. (Unless the triangle is part imaginary)
The length of the hypotenuse of a triangle with one leg 19 cm and the other leg eight cm is: 20.62 cm
If the shortest leg of a 30-60-90 triangle has length 12, the length of the hypotenuse is: 24
The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
Use Pythagoras. h^(2) = a^(2) + b^(2) b^(2) = h^(2) - a^(2) Factor h^(2) = (h - a)(h + a) Substitute b^(2) = (80 ins - 48 inches)(80 ins)( + 48 ins) b^(2) = (32ins)(128 ins) b^(2) = 4096 sq. ins b = sqrt(4096 sq. ins) b = 64 ins. THe Answer. NB For right angled triangles , use Pythagoras NNB The algebraic rearrangement CAN be factored. From your algebra learning . Two squared terms with a positive (+) between them CANNOT be factored. However, Two squared terms with a negative(-) between them CAN be factored. NNNB Do NOT forget to 'square root' both sides at the very end.
Use Trigonometry. Sine(Angle) = opposite/ hypotenuse => angle = Sin^(-1)[opposite/hypotenuse[ Cosine(angle) = adjacent /hypotenuse => angle = Cos^(-1)[adjacent/hypotenuse] Tangent(angle) = opposite/adjacent => angle = Tan^(-1)[opposite/adjacent]. These trig. functions are often reduced to SOH,CAH,TOA. Depending on your calculator the inverse buttons can be Sin^(-1) or ArcSin Cos^9-1) = ArcCos Tan^(-1) = ArcTan For example. The side lengths are 5,12,13 Hence Sin(angle) = opposite/hypotenuse = 5/13 Angle = Sin^(-1) [ 5/13] Angle = 22.61986495.... degrees. or Angle ~ 22.6 ( 1.d.p.). Simillarly for the other angles, but make sure you use the correct Trig. Function.
Area of a right triangle = (1/2 the length of one leg) x (length of the other leg)
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2
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The sine function is used in trigonometric calculations when attempting to find missing side lengths of a right triangle. The sine of an angle in a triangle is equal to the length of the side opposite of that angle divided by the length of the hypotenuse of the triangle. Using this fact you can calculate the length of the hypotenuse if you know an angle measure and the length of one leg of the triangle. You can also calculate the length of a leg of the triangle if you know an angle measure and the length of the hypotenuse.
The other leg length is 16.
Special right triangles include the 45-45-90 triangle and the 30-60-90 triangle. In a 45-45-90 triangle, the legs are equal, and the hypotenuse is ( \sqrt{2} ) times the length of each leg. In a 30-60-90 triangle, the length of the hypotenuse is twice the length of the shorter leg, while the longer leg is ( \sqrt{3} ) times the length of the shorter leg. To solve problems involving these triangles, use these ratios to find unknown side lengths.
If it's a right angle triangle then the other leg will also be 13 units in length and use Pythagoras' theorem if you need to find the length of the hypotenuse.
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